I’ve just finished a big uni project, and I feel like doing something frivolous. Twig has provided me with something to do:
* Twigathy wonders how many kittens is as noisy as a aircraft taking off >_>
Thank you!
We need some guestimates to start off with. I’m going to say that an aircraft taking off is about 120dB (from this page), and a kitten’s mew is about 64dB (quite a noisy kitten). Both these figures are dBSPL.
We will say that we have n kittens, and that their mews are incoherant (i.e. at different phases and frequencies – unless they’re exceedingly well trained kittens). We’re going to assume that they all meow at the same 64dB. The equation to sum sound pressure levels is:
Lpt = Lps + 20 log(n)
Where
Lpt = total sound pressure level (dB)
Lps = sound pressure level from each single source (dB)
n = number of sources
(stolen from Engineering-toolbox.com)
We want to extract the n from the log and make it the subject.
Some algebra later, we get
n = 10 ^ ((Lpt-Lps) / 20)
If we plug in 120dB for Lpt and 64dB for Lps.
n = 10 ^ ((120-64) / 20)
n = 630.957
So, there you have it. It takes 631 kittens all meowing simultaneously to be equivilant to an aircraft taking off.
EDIT: I’ve realised I’ve left a lot of things out, so expect another update with more detail :p